BEN BOUBAKERM oham ed Am ine

Institut Preparatoire aux Etudes D’Ing′enieur De Nabeul University of Carthage CampusUniversitaireM erezka,8000,Nabeul,Tunisia.

Positive Solu tions of Non linear Ellip tic Prob lem in a Non-Sm ooth Planar Dom ain

BEN BOUBAKERM oham ed Am ine?

Institut Preparatoire aux Etudes D’Ing′enieur De Nabeul University of Carthage CampusUniversitaireM erezka,8000,Nabeul,Tunisia.

Received 2Decem ber 2013;A ccep ted 28 June 2014

. Wef indandprove3Ginequal i t ies for theLaplacianGreenfunct ionwi th the D irich let boundary cond ition,w hich are app lied to show the existence of positive continuous solutions of the non linear equation w here V and g are Borelm easurable functions,required to satisfy suitable assum ptions related to a new functional class J.Our app roach uses the Schauder fixed point theorem.

Greenfunct ion;Schauder f ixedpoint theorem;superharmonicfunct ion.

1 In troduction

In this paper,w e w ork in the Euclidean space R2.By Sα,w e denote the dom ain defined by

The objective is to study the existence of con tinuous solu tions for the non linear ellip tic p roblem

w here V and g are Borelm easu rable functions,required to satisfy suitable assum p tions related to a new functional class J.The existence resu lts of p roblem(1.1)have been extensively stud ied w hen V=0 and the special non linearity g(x,t)=p(x)q(t),for both bounded and unbounded dom ain D in(n≥1),w ith sm ooth com pact boundary(see for exam p le[1–4]).On the other hand,in[5–7],the au thors considered the p roblem(1.1) w here there isno restrictionson the sign of g,and D isan unbounded dom ain in(n≥1) w ith a com pact Lipschitz boundary.Then,they p roved the existence of infinitely m any solu tionsp rovided that g is in a certain Kato class.Nam ely,they show ed that there exists a num ber b0＞0 such that for each b∈(0,b0],there existsa positive continuous solution u insatisfying

Theorem1.1.(3G-Theorem)There existsa constant C1=C1(α)＞0 such that forall x,y and z in Sα,wehave

whereδ(x)is the Euclidean distance from x to?Sα.

Thisenablesus to define and study,in Section 4 a new Kato class J of functionson Sα. Let

Definition1.1.Wesay that a Borelmeasurable function q on Sαbelongs to the Kato class Jifq satisfies thefollow ing conditions:

Note that ifα=1,then J is the Kato class K in troduced and stud ied in[8].For a Borel m easurable function q on Sα,let

w here hα(x)=|x|αcos(αarg x),for all x∈Sα.To study the p roblem(1.1)in section 5,w e assum e the follow ing cond ition on V and g:

(H1)The function g is a Borelm easu rable on Sα×(0,∞),continuousw ith respect to the second variable and satisfies

Ourm ain resu lt is the follow ing:

Theorem1.2.Assume(H1)-(H3).Then the problem(1.1)has infinitelymany continuous solutions.M oreprecisely,there existsε0＞0 such thatforeachε∈(0,ε0],thereexistsa solution u of

(1.1),continuouson Sαand satisfying

The follow ing notionsw illbe adop ted:

i)Let f and k be tw o positive functionson a set?.We say that f is com parable to k on?and w e denote fk,if there exists C＞1,such that?x∈?.

iii)B(x,r)denotes the Euclidean open ballof center x and rad ius r.

Throughout this paper,C denotes a generic positive constantw hichm ay vary from line to line and?cdenotes the com p lem entary of?in.

2 Inequalities for the G reen function

Proposition2.1.([10])There existsa constant Cα＞0,such that forall x and y in Sα,wehave

Theorem2.1.([10])Letα∈]0,+∞[{1}.Then,forall x,y∈Sα

Lemma2.1.ThereexistsC=C(α)＞1,such thatforallx,y∈Sα,wehave thefollow ing properties:

Proof.i)Assum e|x|α-1δ(x)|y|α-1δ(y)≤|x-y|2(|x|∨|y|)2(α-1).Let Cαbe the constant defined in Proposition2.1 and x,y∈Sα.Let

Since|x|α-1δ(x)|y|α-1δ(y)≤|x-y|2(|x|∨|y|)2(α-1),it follow s,by Proposition2.1,that

Thus,w e deduce that

Using Proposition 2.1,w e get

By interchanging the role of x and y,w e obtain(i).

ii)Assum e|x-y|2(|x|∨|y|)2(α-1)≤|x|α-1δ(x)|y|α-1δ(y),then,by Proposition 2.1,w e get

In consequence,w e obtain

w hich gives

So,by using Proposition 2.1,w e deduce that

The p roof is com p lete.

Proposition2.2.Thereexists C=C(α)＞0 depending only on Sα,such that forall x,y in Sα

there exists C＞0 such that

Since|xα-yα|?|x-y|(|x|∨|y|)α-1andδ(x)≤|x|,there exists C＞0 such that

ii)The left hand side inequality in(2.7)follow s from(2.8).We p rove the righ t hand side inequality.There are tw o cases to d iscuss:

If|x|α-1δ(x)|y|α-1δ(y)≤|x-y|2(|x|∨|y|)2(α-1),then it follow s by Lemm a 2.1 that

If|x|α-1δ(x)|y|α-1δ(y)≥|x-y|2(|x|∨|y|)2(α-1),then it follow s by Lemm a 2.1 that

The p roof is com p lete.

ProofofTheorem1.1.Since the function z7-→zαis a con form alm app ing from Sαinto the half p lane S1.It follow s from 3G inequality p roved in[8]that,for all x,y and z in Sα

將需要反向計(jì)分的條目進(jìn)行轉(zhuǎn)換后，所有被試的數(shù)據(jù)根據(jù)量表總得分由高到低進(jìn)行排列，以總得分前27%的被試作為高分組，后27%的被試作為低分組，兩組被試每一條目得分的平均數(shù)差異均顯著，ps<0.01。被試每一條目得分與量表總得分之間均呈顯著正相關(guān)，相關(guān)系數(shù)在0.35～0.87之間。

Thus the resu lt follow s from Proposition 2.1.

3 Kato class

Proposition3.1.Let R＞0,then forall x,y∈Sα∩B(0,R),wehave

Proof.We can suppose that|x|≥|y|.Assum e12＜α＜1,then

Assum eα＞1,then

The p roof is com p lete.

Proposition3.2.Letq bea Borelmeasurablefunction on Sαsuch thatq∈J,then foreach R＞0,

Proof.By(2.7)w e have

This im p lies by Proposition 2.1,that for all x,y∈Sα

Since q∈J,then by(1.3)there exists r＞0 such that

The p roof is com p lete.

Proposition3.3.Ifq∈J,then k q k＜+∞.

Proof.Using Proposition 2.1,w e get

Let r＞0 and M＞0.Then,w e have

By(2.3)and Proposition 3.1,w e obtain

The resu lt follow s from(1.3),(1.4)and Proposition 3.2.

Proposition3.4.Let h beapositive superharmonic function in Sαand q in J.Then

Proof.Let h bea positive superharm onic function on Sα.By[11,Theorem 2.1],thereexists a sequence(fn)n∈Nof positivem easu rable function on Sαsuch that

Hence,w e need on ly to verify(3.3)-(3.5)for h(y)=Gα(y,z)uniform ly on Sα.

1.Let r＞0.Then by Theorem 1.1,w e have

Letηand M＞0.By using(2.6),w e get

We obtain(3.3)by using(1.3),(1.4)and Proposition 3.2.

On the other hand,

2.(3.5)follow s imm ed iately by using Theorem 1.1.

Corollary3.1.Letq bea Borelmeasurablefunction in J.Then,

Proof.By using(3.5)w ith h=1 and Proposition 3.3,w e obtain(3.7).Let x0∈Sα.By(2.6) and(3.7)w e get

Finally,(3.9)follow s from(3.8).

Proposition3.5.Letη,μ∈R such thatη＜2＜μandα∈]12,1[.Then thefunctionσdefined on Sαby

is in J.

Proof.Letη,μ∈R such thatη＜2＜μand r＞0.Then w e have

Let us recall that ifα∈]12,1[,then|x-y|(|x|∨|y|)α-1≤21-α|x-y|α.This im p lies by using Lemm a 2.1,that

On the other hand,by Lemm a2.1 there exists C＞1 such that for all y∈?2,xw e have

Since ln(1+t2)≤C tγ,?t≥0,?γ∈](0∨η),2[,then

Now let M＞0,

and show ing that limM-→+∞IM=0.Letε＞0,then there exists r＞0 such that

Then

w here r0=21-αrα.

Fixing this r0＞0 and letting M＞1,w e get

Since the function z7-→zαis a conform alm apping,by using(2.2)w e obtain

The p roof is com p lete.

Lemma3.1.Let hα(x)=|x|αcos(αarg x),x∈Sα.Let M＞0 and r＞0.Then there exists a constant C＞0,such that forall x,y∈Sαsatisfying|x-y|≥r and|y|≤M

4 Proof of Theorem 1.2

Let C(Sα)denotes the space of allbounded con tinuous functions in Sαendow ed w ith the uniform norm k k∞and let

w here Cαis the constant defined in Proposition 2.1.For v∈C1(Sα),w e define

In the follow ing,for sim p licity,w ew rite q(y)=|V(y)|+ψ(y).

Proof.Let x0∈and r＞0.Let M＞|x0|+r,and x,It follow s from(H1) and v≤1/Cαthat

Hence Lv is continuous in Sαuniform ly for v∈C1(Sα).

We next consider x0=∞.Let M＞0 and x∈Sαsuch that|x|≥M+1,then

By(1.4),the second term of the righ t hand side is bounded byε,w henever M is su fficiently large.Note that from Proposition 3.1 and Lemm a 3.1,there exists C＞0 such that

It follow s from Proposition 3.2 and Lebesgue’s convergence theorem that

M oreover,Lε(Gε)isrelatively compact in C(Sα∪{∞}).

Let0＜λ＜1 and define

so it follow s from(H1)that for x∈Sα,w e have

Lemma4.3.Let0＜ε＜ε0.Then Lεis continuouson Gε.

Proof.Let(vk)kbe a sequence in Gεw hich convergesuniform ly to v∈Gε.It follow s from (H1)-(H3)and Lebesgue’s theorem that

Since Lε(Gε)is a relatively com pact fam ily in C(Sα∪{∞}),the pointw ise convergence im p lies the uniform convergence.Therefore k Lεvk-Lεv k∞-→0 as k-→+∞.Thus Lεis continuouson Gε.

ProofofTheorem1.2.Let 0＜ε≤ε0,w hereε0is the positive constant defined in Lemm a

Let u(x)=v(x)hα(x).Then u＞0 in Sα,and u=0 on?Sαsince hαsatisfies these cond itions. A lso,w e have for x∈Sα,

The p roof is com p lete.

Example4.1.Letν＞0,α∈]12,1[andη＜2＜μ.Let h be a Borelm easu rable function on Sαsuch that

Then,there existsε0＞0 such that for eachε∈(0,ε0],the p roblem

has a solution w continuouson Sαand satisfying

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10.4208/jpde.v27.n3.2 Sep tem ber 2014

?Correspond ing au thor.Emailaddress:MohamedAmine.BenBoubaker@ipein.rnu.tn(M.A.Ben Boubaker)

AMSSubjectClassifications:31A10,31A25,31A35,34B15,34B27,31C45,35J65

ChineseLibraryClassifications:O175.5,O175.8